Folks on Reddit had been amused by the primary sentence of this math drawback.


The primary sentence displays what number of math issues are introduced to be “actual world” functions however they appear a bit contrived.
Some dude needs two rectangular enclosures towards his home for some motive. He has 300 ft of fencing. Discover the next:
a) Space when it comes to x
b) Most space
c) Dimensions for max space. Embrace items in your reply.


As standard, watch the video for an answer.
Humorous Math Downside
Or maintain studying.
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“All will probably be nicely in case you use your thoughts to your choices, and thoughts solely your choices.” Since 2007, I’ve devoted my life to sharing the enjoyment of sport idea and arithmetic. MindYourDecisions now has over 1,000 free articles with no advertisements because of group help! Assist out and get early entry to posts with a pledge on Patreon.
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Reply To Humorous Math Downside
(Just about all posts are transcribed rapidly after I make the movies for them–please let me know if there are any typos/errors and I’ll appropriate them, thanks).
If one facet of the rectangle is x, then the 2 sides parallel to it additionally equal x. The fencing enclosure makes use of the home for one facet, and the remaining fence can be utilized for the fence. The three vertical fences whole 3x, so the remaining fencing size is 300 – 3x.


Thus the realm of the fence is its top occasions its width which is:
A(x) = x(300 – 3x) = 300x – 3x2
How can we maximize the realm?
Parabola symmetry
Discover the realm operate will be represented by a parabola with minimal values at x = 0 and 300 – 3x = 0, or x = 100. The world could have constructive values in between. By symmetry of a parabola, this parabola has its most precisely midway between the 2 x intercepts, so its most is at x = 50. So the scale are x = 50 ft and 300 – 3x = 150 ft, giving a most space of fifty(150) = 7500 ft2.
Finishing the sq.
A(x)
= 300x – 3x2
= -3(x2 – 100x)
= -3(x2 – 100x + 502 – 502)
= -3((x – 50)2 – 502)
= 3(502) – 3(x – 50)2
= 7500 – 3(x – 50)2
The squared time period is non-negative, so the second time period solely subtracts from the constructive 7500 potential. We maximize the realm by subtracting as little as doable, which occurs when x = 50. Thus we once more discover the rectangle has a most space of 7500 sq. ft and dimensions of fifty ft by 150 ft.
Calculus
It is a simple calculation.
A‘(x) = 300 – 6x
A”(x) = -6
A‘(x) = 300 – 6x = 0
x = 300/6 = 50
The rectangle has dimensions of x = 50 ft and 300 – 3x = 150 ft with a most space of fifty(150) = 7500 ft squared.
Reference
Reddit
https://www.reddit.com/r/humorous/feedback/74c34o/hands_down_best_first_sentence_of_a_math_problem/
Yard backyard
https://fox11online.com/information/offbeat/frontdoor-com-chicken-coop-raised-bed-garden-do-it-yourself-projects-google-search-terms-study-survey-poll
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